A bullet of mass 20 g is moving with initial speed of `1ms^(-1)` just before it starts penetrting a mud wall of thickness 20 cm. If the wall offers a mean resistance of `2.5xx10^(-2)N`, the speed (in m/s) of the bullet after emerging from the other side of the wall is nearly equal to:

Explanation

To solve the problem, we need to find the final speed of the bullet after it penetrates the mud wall. We can use the principles of Newton's laws of motion and the equations of motion.

### Step-by-Step Solution:

1. **Convert Units**:
- The mass of the bullet is given as 20 g. We need to convert this to kilograms:
\[
m = 20 \, \text{g} = 20 \times 10^{-3} \, \text{kg} = 0.02 \, \text{kg}
...