A solid sphere of mass M and radius R is divided into two unequal parts. The first parts has a mass of `(7M)/8` and is converted into a uniform disc of radius 2R. The second part is converted into a uniform solid sphere. Let `I_(1)` be the moment of inertia of the uniform disc about its axis and `I_(2)` be the moment of inertia of the sphere made from remaining part about its axis. The ratio `I_(1)//I_(2)` is `140/x`. Find the value of x.

Explanation

To solve the problem, we need to find the moment of inertia of two objects created from a solid sphere: a disc and a smaller sphere. We will use the formulas for the moment of inertia and the conservation of volume to derive the necessary values.

### Step-by-Step Solution:

1. **Identify the Masses and Radii**:
- The original solid sphere has mass \( M \) and radius \( R \).
- The first part has a mass of \( \frac{7M}{8} \) and is converted into a uniform disc with a radius of \( 2R \).
- The mass of the second part, which is converted into a solid sphere, is:
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