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A ring of mass 10 kg and diameter 0.4m i...

A ring of mass 10 kg and diameter 0.4m is rotated about its axis. If it makes 2100 revolutions per minute, then its angular momentum (in kg `m^(2)//s`) will be

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To find the angular momentum of the ring, we can use the formula for angular momentum \( L \) given by: \[ L = I \omega \] where \( I \) is the moment of inertia and \( \omega \) is the angular velocity. ...
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