A particle of mass `m=5 kg` is moving with a uniform speed `v=3 sqrt(2)` in the `XOY` plane along the line `Y=X+4`. The magnitude of the angular momentum of the particle about the origin is

Explanation

`y=x+4` line has been in the figure. When x=0, y=4 so OP =4
the slope of the line can be obtained by comparing with the equation of line `y=mx+c`
`m=tan theta =1impliestheta =45^(@)`
`/_OQP=/_OPQ=45^(@)`
Length of the perpendicular drawn =OR
In `DeltaOPR, (OR)/(OP)=sin 45^(@)`
`impliesOR=OP sin 45^(@)=4xx1/(sqrt(2))=4/(sqrt(2))=2sqrt(2)`
Angular momentum of particle along this line
`=rxxmv=2sqrt(2)xx5xx3sqrt(2)=60 `units