In an environment, brass and steel wires of lengh 1 m each with areas of cross section `1mm^(2)` are used. The wires are connected in series ankd one end of the combined wie is connected toa rigid support and other endis subjected to elongation. The stress (in `Nm^(-2)`) requird to produce a net elongation of 0.2 mm is
[Given the Young's modulus for steel and brass are respectively `120xx10^(9)N//m^(2)` and `60xx10^(9)N//m^(2)`)

Explanation

To solve the problem, we need to determine the stress required to produce a net elongation of 0.2 mm in a system of brass and steel wires connected in series.

### Step-by-Step Solution:

1. **Understanding the Setup**:
- We have two wires: one made of brass and the other made of steel.
- Both wires have a length of \( L = 1 \, \text{m} \) and a cross-sectional area of \( A = 1 \, \text{mm}^2 = 1 \times 10^{-6} \, \text{m}^2 \).
- The Young's modulus for brass is \( Y_b = 60 \times 10^9 \, \text{N/m}^2 \) and for steel is \( Y_s = 120 \times 10^9 \, \text{N/m}^2 \).
...