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A wire of length 50 cm and cross section...

A wire of length `50 cm` and cross sectional area of 1 sq. mm is extended by `1mm`. The required work will be `(Y=2xx10^(10) Nm^(-2))`

Text Solution

Verified by Experts

`W=(YAl^(2))/(2L)=((2xx10^(10)xx10^(-6))xx(10^(-3))^(2))/(2xx50xx10^(-2))=2xx10^(-2)J`
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