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A submarine experiences a pressure of 5....

A submarine experiences a pressure of `5.05xx10^(6)Pa` at a depth of `d_(1)` in a sea When it goes futher to a depth of `d_(2)`. It experiences a pressure of `8.08xx10^(6)Pa`. The `d_(2)-d_(1)` is approximately (density of water `=10^(3)kg//m^(3)` and acceleration due to gravity `=10ms^(-2))`

Text Solution

Verified by Experts

`P_(1)=P_(0)+rhogd_(1)`
`P_(2)=P_(0)+rhogd_(2)`
`DeltaP=P_(2)-P_(1)=rhog Deltad`
`3.03xx10^(6)=10^(3)xx10xxDeltad`
`impliesDd=300m,`
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