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Two kg of a monoatomic gas is at a press...

Two kg of a monoatomic gas is at a pressure of `4 xx 10^(4) N//m^(2)`. The density of the gas is `8 kg//m^(3)`. What is the order of energy of the gas due to its thermal motion ?

Text Solution

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Thermal energy of N molecule
`=N(3/2kT)`
`=N/(N_(A))3/2 RT =3/2 (nRT)=3/2 PV`
`=3/2P(m/(rho))=3/2P(2/8)`
`=3/2xx4xx10^(4)xx2/8=1.5xx10^(4)`
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