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10^(22) particles each of mass 10^(-26)...

`10^(22) ` particles each of mass `10^(-26) Kg` are striking perpendicular on a wall of area `1 m^(2)` with speed `10^(4)m//s` in `1 sec`. The pressure on the well if collision are perfectly elastic is : (A) `2 N//m^(2)` (B) `4N//m^(2)` (C) `6N//m^(2)` (D) `8 N//m^(2)`

Text Solution

Verified by Experts

Rate of change of momentum during collision
`=(mv-(-mv))/(Deltat)=(2mv)/(Deltat)N`
so pressure
`P=(Nxx(2mv))/(DeltatxxA)=(10^(22)xx2xx20^(-26)xx10^(4))/(1xx1)=2N//m^(2)`
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