Home
Class 12
PHYSICS
Two simple pendulums of length 1m and 1....

Two simple pendulums of length 1m and 1.21 m are started oscillating from some position. Find the minimum time (in second) after which they again start from same position.

Text Solution

AI Generated Solution

To find the minimum time after which two simple pendulums of lengths 1 m and 1.21 m will start from the same position again, we will follow these steps: ### Step 1: Calculate the Time Period of Each Pendulum The time period \( T \) of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \] ...
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 14: (WAVES)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 15 : (ELECTRIC CHARGES AND FIELDS)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 12 (KINETIC THEORY)|15 Videos
  • ATOMS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos
  • COMMUNICATION SYSTEM

    DISHA PUBLICATION|Exercise EXERCISE-2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

Two simple pendulums of lengths 100 cm and 144cm start oscillating together at time t = 0. The minimum time after which they swing together is (take g=pi^(2)ms^(-2) )

Two simple pendulums of length 100m and 121m start swinging together. They will swing together again after

The pendulums of lengths 100 cm and 110.25 cm start oscillating in phase. After how many oscillation will they again be in same phase ?

Two pendulums of length 90 cm and 100 cm start oscillating in phase. After how many osxillations will they b again in the same phase ?

Two simple pendulums of lengths 1.44 m and 1 m start swinging together. After how many vibrations will they again start swinging together

Two simple pendulum of length l and 16l are released from the same phase together. They will be at the same time phase after a minimum time.

Two simple pendulums A and B having lengths l and (l)/(4) respectively are released from the position as shown in Fig. Calculate the time (in seconds) after which the two strings become parallel for the first time. (Take l=(90)/(pi^2) m and g=10(m)/(s^2) .

Two simple pendulums of length 1m and 16m respectively are both given small displacements in the same direction at the same instant. After how many oscillations of the shorter pendulum will, the two pendulums vibrate in the same phase ?

Two pendulums of lengths 200 cm and 220.50 cm start oscillating in phase. After how many oscillations will they be in same phase for the first time ?