Two particles execute SHM with same frequency and amplitude along the same straight line. They cross each other , at a point midway between the mean and the extreme position. Find the Phase difference between them.

Explanation

For first particle
`x=A sin phi_(1)`
or `A/2=A sin phi_(1)impliessin phi_(1)=1/2` or `phi_(1)=(pi)/6`
For second particle
`A/2=A sin phi_(2)=(pi)/6` or `pi-(pi)/6=(5pi)/6`
As `phi_(1)!=phi_(2):.phi_(2)=(5pi)/6`
Now `phi_(2)-phi_(1)=(5pi)/6-(pi)/6=(2pi)/3`