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A mass (M) is suspended from a spring of...

A mass (M) is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes `(5T)/3`. Then the ratio of `m/M` is .

Text Solution

Verified by Experts

`T=2sqrtpisqrt(M/k)` and `(5T)/3=2pisqrt((M+m)/k)`
After simplifying above equations we get
`m/M=16/9`
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