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The amplitude of a wave disturbance prop...

The amplitude of a wave disturbance propagating along positive X-axis is given by `=1/(1+x^(2))` at t=0 and `y=1/[1+(x-2)^(2)]` at t=4 s where x and y are in metre. The shape of wave diturbance does not change with time. The velocity of the wave is

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The equation of the wave at any time can be obtained by putting (x-vt) in place of x in the given expression so we have
`y=1/(1+(x-vt)^(2))`………I
Given `y=1/(1+(x-2)^(2))` at `t=4s` ii
On comparing equations I and ii we get
vt=2
As t = 4s `:.v=2/t=2/4=0.5m//s`
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