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Pipe A has length twice the pipe B. Pipe...

Pipe A has length twice the pipe B. Pipe A has both ends open and pipe B has one end open. Which harmonics of pipe A have a frequency that matches a resonance frequency of pipe B.

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To solve the problem, we need to determine which harmonics of pipe A (which is open at both ends) resonate at the same frequency as the harmonics of pipe B (which is open at one end and closed at the other). ### Step-by-Step Solution: 1. **Define Lengths of Pipes**: - Let the length of pipe B be \( L \). - Therefore, the length of pipe A will be \( 2L \) (since pipe A is twice the length of pipe B). ...
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