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An electric dipole is placed at an angle...

An electric dipole is placed at an angle of `30^(@)` with an electric field intensity `2xx10^(5)N//C`. It experiences a torque equal to `4Nm`. The charge on the dipole, if the dipole is length is `2 cm`, is

Text Solution

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Torque `vec(tau)=vecpxxvecE=pEsin theta`
`4=pxx2xx10^(5)xxsin30^(@)`
or `p=4/(2xx10^(5)xxsin30^(@))=4xx10^(-5)Cm`
Dipole moment `p=qxxl`
`q=p/l=(4xx10^(-5))/0.02=2xx10^(-3)C=2mC`
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