A point charge causes an electric flux of `-1.0xx10^(3) N m^(2)//C` to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface ? (b) What is the is the value of the point charge ?

Explanation

According to Gauss.s theorem electric flux through a closed surface `S=q//epsilon_(0) `
Where q=total charge enclosed by S
Electric flux pass through the spherical of Gausian surface is independent on the radius of a Gaussian surface but depends on the charge enclosed by a Gaussian surface. On increasing the radius of Gaussian surface three times, but the charge enclosed by a Gaussian surface remain the same. Therefore, the electric flux pass throgh the Gaussian surface remains the same.