An electric field of `1000 V//m` is applied to an electric dipole at angle of `45^(@)`. The value of electric dipole moment is `10^(-29) C.m` .What is the potential energy of the electric dipole ?

Explanation

Potential of a dipole is given by
`U=-vecP.vecE`
`=-PEcos theta`
[Where `theta=` angle between dipole and perpendicular to the field]
`=-(10^(29))(10^(3))cos 45^(@)`
`=-0.707xx10^(-26)J`
`=-7xx10^(-27)J`