Voltage rating of a parallel plate capacitor is 500V. Its dielectric can withstand a maximum electric field of `10^(6)V//m`. The plate area is `10^(-4)m^(2)`. What is the dielectric constant if the capacitance is 15pF? (given `in_(0)=8.86xx10^(-12)C^(2)//Nm^(2)`)

The capacitance of a parallel plate capacitor with air as the medium is 3muF . With the introduction of dielectric medium between the plates, the capacitance becomes 15muF . What is the permittivity of the medium? (epsi_(0)=8.85xx10^(-12)C^(2)//Nm^(2))

The capacitance of a parallel plate capacitor with air as medium is 3muF . With the introduction of a dielectric medium between the plates, the capacitance becomes 15muF . What is the permittivity of the medium? (epsi_(0)=8.85xx10^(-12)C^(2)//Nm^(2))

A capacitor of capacitance C=15pF is charged with voltage V=500V . The electric field inside the capacitor with dielectric is 10^(6)V//m and the area of the plate 10^(-4)m^(2) , then the dielectric constant of the medium is : (._(epsilon0)=8.85xx10^(-12) in S.I units) (A) 12.47 (B) 8.47 (C) 10.85 (D) 14.85

The potential difference between the plates of a parallel plate capacitor is changing at the rate of 10^(6)V/s .If the capacitance is 2 mu F ,the displacement current in the dielectric of the capacitor will be

The capacitance of a parallel plate capacitor is 10muF . When a dielectric plate is introduced in between the plates, its potential becomes 1/4th of its original value. What is the value of the dielectric constant of the plate introduced?

Each plate of a parallel plate condenser has surface area of 5 cm^(2) . The distance between the plates is 2 mm. The dielectric constant of the medium between the plates is 5. Then the capacity of the condenser is (epsi_(0) = 8.85 xx 10^(-12) C^(2)//Nm^(2))

The potential difference between the plates of a parallel plate capacitor of capacitance 2 mu F is changing at the rate of 10^(5)V//s . What is the displacement current in the dielectric of the capacitor?

A parallel-plate capacitor having plate are 100 cm ^2 and separation 1.0 mm holds a charge of 0.12 muC when connected to a 120 V battery. Find the dielectric constant of the material filling the gap.

The voltage between the plates of a parallel plate capacitor of capacitance 1.0muF is changing at rate of 1.0 V//s . Find displacement current

A dielectric of thickness 5cm and dielectric constant 10 is introduced between the plates of a parallel plate capacitor having plate area 500 sq. cm and separation between the plates 10cm. The capacitance of the capacitor with dielectric slab is (epsi_(0) = 8.8 xx 10^(-12)C^(2)//N-m^(2))