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A current of 2 mA was passed through an ...

A current of 2 mA was passed through an unknown resistor which dissipated a power of 4.4 W. Dissipated power when an ideal power supply of 11 V is connected across it is

Text Solution

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Power `P=I^(2)R`
`4.4=4xx10^(-6)xxR`
`impliesR=1.1xx10^(6)Omega`
When supply of 11 v is connected
Power `P.=(V^(2))/R=(11^(2))/(1.1)xx(11^(2))/(1.1)xx10^(-6)=11xx10^(-5)W`
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