Home
Class 12
PHYSICS
A particle having the same charge as of ...

A particle having the same charge as of electron moves in a circular path of radius 0.5 cm under the influence of a magnetic field of 0.5 T. If an electric field of 100V/m makes it to move in a straight path, then the mass of the particle is ( Given charge of electron `= 1.6 xx 10^(-19)C`)

Text Solution

Verified by Experts

As particle is moving along a circular path
`:.R=(mv)/(qB)` ……I
Path is straight line then
`qE=qvB`
`E=vBimpliesv=E/B`….ii
From equation I and ii
`m=(qB^(2)R)/E=(1.6xx10^(-19)xx(0.5)^(2)xx0.5xx10^(-2))/100`
`:.m=2.0xx10^(-24)kg`
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 19 : (MAGNETISM AND MATTER)|14 Videos

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 20 : (ELECTROMAGNETIC INDUCTION)|15 Videos

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 17 : (CURRENT ELECTRICITY)|13 Videos

  • ATOMS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos

  • COMMUNICATION SYSTEM

    DISHA PUBLICATION|Exercise EXERCISE-2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

A particle moves in a circle of radius 1.0 cm under the action of a magnetic field of 0.40 T .An electric field of 200 V//m makes the path straight.Find the charge/mass ratio of the particle.

A particle moves in a circle of diamater 1.0 cm under the action of magnetic field of 0.40 T, An electric field of 200 V m^(-1) makes the path straight. Find the charges/mass ration of the particle.

An electron move in a circular path of radius 2 cm under the influence of a magnetic field of 0.1 teals applied perpendicular to its plane of motion . Calculate the de Broglie wavelength of electron.

An electron is moving on a circular path of radius r with speed v in a transverse magnetic field B. e/m for it will be

Charged particle of charge q mass m moves in a circular path of radius r under the action of force F .The equivalent current is

Charged particle of charge q mass m moves in a circular path of radius r under the action of force F .The equivalent current is

The momentum of alpha -particles moving in a circular path of radius 10 cm in a perpendicular magnetic field of 0.05 tesla will be :

A particle having charge 100 times that of an electron is revolving in a circular path of radius 0.8m with one rotation per second. The magnetic field produced at the centre is

A particle having a charge 100 times that of an electron is revolution in a circular path of radius 0.4 m, with 1 rev/s. What is the magnitude of the magnetic field produced at its center?

If a charged particle having charge q is moving in a circular path of radius R with a uniform speed u, what would be the magnetic field at the centre?