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Find the magnitude of the magnetic field...

Find the magnitude of the magnetic fieldat the center of an equilateral triangular loop of side length 1m which is carrying a current of 10A. ( Take `mu_(0) = 4pi xx 10^(-7) NA^(-2))`

Text Solution

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`r=(1/3)(a sin 60)`
`r=a/3xx(sqrt(3))/2=(a/(2sqrt(3)))`
`B_(0)=3[(mu_(0)I)/(4 pi r)(sin 50 +sin 60)]`
`=(3mu_(0)I)/(4pi (a/(2sqrt(3))))xx(2)((sqrt(3))/2)=9/3((mu_(0)I)/(pia))`
`=(9xx2xx10^(-7)xx10)/1=18muT`
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