Home
Class 12
PHYSICS
The magnetic field of earth at the equat...

The magnetic field of earth at the equator is approximately `4xx10^(-5)T`. The radius of earth is `6.4xx10^(6)m`. Then the dipole moment (in `A-m^(2)`) of the earth will be nearly of the order of

Text Solution

AI Generated Solution

To find the dipole moment of the Earth using the given magnetic field at the equator and the radius of the Earth, we can use the formula for the magnetic field \( B \) due to a magnetic dipole moment \( m \): \[ B = \frac{\mu_0}{4\pi} \cdot \frac{m}{r^3} \] Where: - \( B \) is the magnetic field (in tesla), ...
Promotional Banner

Topper's Solved these Questions

  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 20 : (ELECTROMAGNETIC INDUCTION)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER -21 : (ALTERNATING CURRENT)|15 Videos
  • CHAPTERWISE NUMERIC /INTEGER ANSWER QUESTIONS

    DISHA PUBLICATION|Exercise CHAPTER 18- (MOVING CHARGES AND MAGNETISM)|15 Videos
  • ATOMS

    DISHA PUBLICATION|Exercise EXERCISE-2: CONCEPT APPLICATOR|30 Videos
  • COMMUNICATION SYSTEM

    DISHA PUBLICATION|Exercise EXERCISE-2 : Concept Applicator|30 Videos

Similar Questions

Explore conceptually related problems

The magnetic field of earth at the equator is approximately 4 x× 10^(-5) T. The radius of earth is 6.4 x× 10^(6) m. Then the dipole moment of the earth will be nearly of the order of:

The earth's magnetic field at the equator is approximately 0*4G , Estimate the earth's dipole moment.

The magnetic field at a point on magnetic equator is 3*1xx10^-5T . If radius of earth is taken as 6400km , what is magnetic moment of the assumed dipole at the centre of earth?

The magnetic field at a point on the magnetic equator is found to be 3.1 xx 10^(-5) T . Taking the earth's radius to be 6400 km, calculate the magneitc moment of the assumed dipole at the earth's centre.

The Earth's magnetic field at some place on magnetic equator of Earth is 0.5 xx 10^(-4)T. Consider the radius of Earth at that place as 6400 km. Then, magnetic dipole moment of the Earth is .... Am^(2) (mu=4pixx 10^(-7)TmA^(-1))

The magnetic field at a point on the magnetic equator is found to be 3*1xx10^-5T . Taking the earth's radius to be 6400km , calculate the magnetic moment of the assumed dipole at the earth's centre.

Give the order of the following : Mean radius of earth ( 6.37xx10^(6)m )

A proton is to circulate the earth along the equator with a speed of 1.0 xx 10^(7) m/s. The minimum magnetic field which should be created at the equator for this purpose. (The mass of proton =1.7 xx 10^(-27) kg and radius of earth = 6.37 xx 10^(6) m.) will be (in "Wb/m"^(2) )

The mean radius of the earth's orbit of mercury is 6xx10^(10)m . The mercury will revolve around the sun in nearly