The current in an RL circuits drops from 1.0 A to 10 mA in the 10 second following removal of the battery from the circuti. If L is 10 H, find the resistance R (in ohm) in the circuit.

Explanation

To solve the problem, we need to find the resistance \( R \) in an RL circuit where the current drops from \( 1.0 \, \text{A} \) to \( 10 \, \text{mA} \) in \( 10 \, \text{s} \) after the battery is removed. The inductance \( L \) is given as \( 10 \, \text{H} \).

### Step-by-Step Solution:

1. **Convert the Current Values**:
- Initial current \( I_0 = 1.0 \, \text{A} \)
- Final current \( I = 10 \, \text{mA} = 10 \times 10^{-3} \, \text{A} = 0.01 \, \text{A} \)

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