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An airplane with a 20 wingspread is flyi...

An airplane with a 20 wingspread is flying at 250m/s straight south parallel to the earth's surface. The earths magnetic field has a horizontal component of `2xx10^(-3)Wb//m^(2)` and the dip angle is `60^(@)`. Calculate the induced e.m.f. between the plane tips.

Text Solution

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We have `tan theta=(B_(V))/(B_(H))`
`:.B_(V)=B_(H) tan theta`
`=2xx10^(-5)xxtan 60^(@)`
`=2xx10^(-5)xxtan 60^(@)`
`=2sqrt(3)xx10^(-5)T`
The induced emf `e=B_(v)vl`
`=(2sqrtS(3)xx10^(-5))xx250xx20`
`=0.173V`
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