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The self induced emf of a coil is 25 vol...

The self induced emf of a coil is 25 volts. When the current in it is changed at uniformed rate from 10 A to 25 A in 1s, the change in the energy of the inductances is

Text Solution

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According to faraday.s law of electromagnetic inductio `e=(-dphi)/(dt)`
`Lxx(di)/(dt)=25impliesLxx15/1=25`
or `L=5/3H`
Change in the energy of the inductance
`DeltaE=1/2L(i_(1)^(2)-i_(2)^(2))=1/2xx5/3xx(25^(2)-10^(2))`
`=5/6xx525=437.5J`
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