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A circular disc of radius 0.2 m is place...

A circular disc of radius `0.2 m` is placed in a uniform magnetic fied of induction `(1)/(pi) ((Wb)/(m^(2)))`
in such a way that its axis makes an angle of `60^(@)` with The magnetic flux linked with the disc is

Text Solution

Verified by Experts

Here `B=1/p(Wb//m^(2))`
`theta=60^(@)`
Area normal to the plane of the disc
`=pr^(2)cos 60^(@)=(pr^(2))/2`
Flux = B`xx` normal area
`=(0.2.0.2)/2=0.02`Wb
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