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A coil has a resistance of 10 Omega and ...

A coil has a resistance of `10 Omega` and an inductance of `0.4` henry. It is connected to an AC source of `6.5 V, 30/(pi) Hz`. Find the average power consumed in the circuit.

Text Solution

Verified by Experts

Average power consumed is given by
`P=(V_(rms)^(2)R)/(Z^(2))`
Where `Z=sqrt(R^(2)+(omegaL)^(2))=sqrt(10^(2)+(2pixx30/(pi)xx0.4)^(2))`
`=26Omega`
`:.:=(6.5^(@)xx10)/(26^(@))=0.625W`
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