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The magnetic field of a plane electromag...

The magnetic field of a plane electromagnetic wave is given by: `vec(B)=B_(0)hat(i)-[cos(kz- omegat)]+B_(1)hat(j)cos(kz+omegat)` where `B_(0)=3xx10^(-5)T` and `B_(1)=2xx10^(-6)T`. The rms value of the force experienced by a stationary charge `Q=10^(-4)C` at `z=0` is close to:

Text Solution

Verified by Experts

`B_(0)=sqrt(B_(0)^(2)+B_(1)^(2))=sqrt(30^(2)+2^(2))xx10^(-6)`
`~~30xx10^(-6)T`
`:.E_(0)=cB=3xx10^(8)xx30xx10^(-6)`
`=9xx10^(3)`V/m
`E_(rms)=(E_(0))/(sqrt(2))=9/(sqrt(2))xx10^(3)V//m`
Force on the charge
`F=F_(rms)Q=9/(sqrt(2))xx10^(3)xx10^(-4)=0.64V`
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