A system of three polarizers `P_(1),P_(2),P_(3)` is set up such that the pass axis of `P_(3)` is crossed with respect to that of `P_(1)`. The pass axis of `P_(2)` is incined at `60^(@)` to the pass axis of `P_(3)`. When a beam of unpolarized light of intensity `I_(0)` is incident on `P_(1)` the intensity of light transmitted by the three polarizes is I.The ratio `(I_(0)//I)` equals (nearly):

Explanation

To solve the problem of the three polarizers \( P_1, P_2, P_3 \) and the intensity of light transmitted through them, we will follow these steps:

### Step 1: Understand the Configuration of Polarizers
- The pass axis of \( P_1 \) is at \( 0^\circ \).
- The pass axis of \( P_3 \) is at \( 90^\circ \) with respect to \( P_1 \).
- The pass axis of \( P_2 \) is inclined at \( 60^\circ \) to the pass axis of \( P_3 \). Therefore, the angle between \( P_1 \) and \( P_2 \) is \( 30^\circ \) (since \( 90^\circ - 60^\circ = 30^\circ \)).

### Step 2: Apply Malus's Law
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