Using a nuclear counter the count rate o...

Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t=0 it was 1600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per seconds, at t=6, seconds is close to :

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According to question at `t=0, A_(0)=(dN)/(dt)=1600` C/s
and at t=8s, A=100C/s
`:.A/(A_(0))=(1/16)`
Therefore half life period `t_(1//2)=2s`
`:.` Activity at t=6s `=1600(1/2)^(3)=200C//s`

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Using a nuclear counter the count rate of emitted particles from a radioactive source is measured. At t = 0 seconds it was 25600 counts per second and t = 8 seconds it was 100 counts per second. The count rate observed, as counts per second, at t = 6 seconds is close to:

150

400

360

200

The initial count rate for a radioactive source was found to be 1600 count/sec.and t = 8 sec this rate was 100 count/sec. What was the count rate at t = 6 [in counts/sec]-

`4000`

`300`

`200`

`150`

The count rate observed from a radioactive source at t second was N_0 and at 4t second it was (N_0)/(16) . The count rate observed at (11/2)t second will be

`(N_0)/(128)`

`(N_0)/(64)`

`(N_0)/(32)`

None of these