The major product of the following reaction is :
`C_6H_5CH_2-overset(CH_3)overset(|)underset(Br)underset(|)(C)-CH_2-CH_3overset(C_2H_5ONa)underset(C_2H_5OH)rarr`

Options

A. `C_6H_5CH_2-overset(CH_3)overset(|)underset(OC_2H_5)underset(|)C-CH_2-CH_3`
B. `C_6H_5CH_2=underset(CH_3)underset(|)C-CH_2-CH_3`
C. `C_6H_5CH_2-underset(CH_3)underset(|)C=CHCH_3`
D. `C_6H_5CH_2-underset(CH_2CH_3)underset(|)C=CH_2`

Explanation

To determine the major product of the given reaction, we will analyze the structure and the reaction conditions step by step.

### Step 1: Identify the Reactants
The reactants provided are:
- A haloalkane: `C6H5CH2C(CH3)Br`
- A base: `C2H5ONa` in `C2H5OH`

### Step 2: Analyze the Structure
The haloalkane can be broken down as follows:
- `C6H5` represents a phenyl group (benzene ring).
- `CH2` is connected to the phenyl group.
- `C(CH3)` indicates a carbon attached to a methyl group (isopropyl).
- `Br` is the leaving group.

### Step 3: Reaction Mechanism
The base `C2H5ONa` can act as a nucleophile or a base. However, due to steric hindrance around the carbon attached to the bromine (Br), it is more likely to act as a base rather than a nucleophile.

### Step 4: Base Action
The base will abstract a proton (H+) from the adjacent carbon. There are two possible hydrogens that can be abstracted:
1. The hydrogen attached to the carbon adjacent to the Br (C(CH3)).
2. The hydrogen attached to the carbon in the `C6H5CH2` group.

### Step 5: Determine the More Stable Product
When the base abstracts the hydrogen from the carbon adjacent to the Br (C(CH3)), the resulting structure will allow for the formation of a double bond between the `C6H5CH2` and the carbon that was previously attached to the Br. This results in the formation of an alkene.

### Step 6: Draw the Major Product
The major product after the elimination reaction will be:
- `C6H5CH=CH(CH3)`

### Conclusion
The major product of the reaction is an alkene, specifically `C6H5CH=CH(CH3)`.

### Final Answer
The major product of the reaction is option B: `C6H5CH=CH(CH3)`.

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