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In a measurement of quantum efficiency o...

In a measurement of quantum efficiency of photosynthesis in green plants, it was found that 10 quanta of red light of wavelength 6850 Å were needed to release one molecule of `O_(2)`. The average energy storage in this process for 1 mol `O_(2)` evolved is 112 Kcal.
What is the energy conversion efficieny in this experiment?
Given: 1 cal =4.18 J, `N_(A)=6xx10^(23),h=6.63xx10^(-34)` J.s

Text Solution

Verified by Experts

The correct Answer is:
26.9
`E = (hc)/lambda = 2..9 xx 10^(-19)` J
Total energy of 10 quanta
`rArr 10 xx 2.9 xx 10^(-19) rArr 29 xx 10^(-19)` J
Energy stored for process
`=(112 xx 4.18 xx 10^(3))/(6 xx 10^(23)) =7.80 xx 10^(-19)` J
% efficiency `=(7.8 xx 10^(-19))/(29 xx 10^(-19)) xx 100 rArr 26.9%`
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