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An element undergoes a reaction as show...

An element undergoes a reaction as shown `sx+2e^(-)tox^(-2)`
Energy released `=30.87` ev/atom. If the energy released is used to dissociated `4g` to `H_(2)` molecules equally into `H^(+)` and `H^(+)` is excited state of `H` atoms where the electron travels in orbit whose circumference equal to four times its de -roglie's wavelength. Determine the minimum number of moles of `x` that would be required.
Given IE of `H=13.6` ev/atom, bond energy of `H_(2)=4.526`v/molecule

Text Solution

Verified by Experts

The correct Answer is:
2
`2pi r = 4 lambda, n=4`
Total energy required + total energy released =0
`2 xx 4.526 xx N_(A) + 2 xx 13.6 xx N_(A)+ 2 xx 13.6 xx (1-1/16) xx N_(A) -30.87 xx x xx N_(A)=0`
x=2
`therefore` moles of x required =2
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An element undergoes s reaction as show - X+2e^(-) rarrX^(2-) , energy relesed =30.87eV//"atom" . If the energy released ,is used to dissociate 8 gms of H_(2) molecules,equally into H^(+) and H^(ast) ,where H^(ast) is an exicted state of H atoms where the electron travels in orbit whose circumference equal to four times its de Broglie's wavelenght . (a) Calculate the excited statue of H (b) Determine the least amount of X that would be required . Given : IE of H = 13.6 eV//"atom" , Bond energy of H_(2) =4.526 eV//"molecule" .

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