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A certain day absorbs lights of lamda=40...

A certain day absorbs lights of `lamda=400` nm and then fluorescence light of wavelength `500` mn. Assuming that under given condition `40%` of the absorbed energy is re-emitted as fluorescence, calculate the ratio of quanta obserbed to number of quanta emitted out.

Text Solution

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The correct Answer is:
2
`E_(abs) xx 40/100= E_("Emitted")`
`n_(ab) xx (hc)/(400) xx 40/100 = n_(cm) xx (hc)/500`
`n_(ab)/n_(cm) = 400/500 xx 100/40 =2`
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