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For the coagulation of 500mL of arseniou...

For the coagulation of `500mL` of arsenious sulphide sol, `2mL` of `1MNaCl` is required. What is the flocculation value of `NaCl` ?

Text Solution

Verified by Experts

The correct Answer is:
4
2 mL of 1 M NaCl contains `NaCl = 2/100 = 2` mole. Thus 500 mL of `As_(2)S_(3)` sol require NaCl for complete coagulation = 2m mole
Hence, 1 L, i.e. 1000 mL of the require NaCl for complete coagulation = 4 m mole
Therefore, flocculation value of NaCl = 4
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