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Considering H2O as a weak field ligand, ...

Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)

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The correct Answer is:
5
Since `H_(2)O` is a weak ligand, it will not cause pairing of electrons in the metal ion `Mn^(2+)`. Thus electronic configuration of the metal `(Mn^(2+))` in the complex will be
`""_(25)Mn^(2+): 1s^(2) 2s^(2) 2p^(6)3s^(2)3p^(6)3d^(5)`
i.e. 5 unpaired electrons.
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