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d/dx[sqrt((1+sinx)/(1-sinx))]...

`d/dx[sqrt((1+sinx)/(1-sinx))]`

Text Solution

Verified by Experts

The correct Answer is:
`secx(secx+tanx)`
`y=(sqrt(1+sinx))/(sqrt(1-sinx))xx(sqrt(1+sinx))/(sqrt(1+sinx))=((1+sinx))/(cosx)=(secx+tanx)`
`rArr(dy)/(dx)=(secxtanx+sec^(2)x)=secx(secx+tanx).`
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