Home
Class 12
MATHS
log(e) 10.02, given that log(e) 10 = 2.3...

`log_(e) 10.02`, given that `log_(e) 10 = 2.3026`

Text Solution

Verified by Experts

The correct Answer is:
2.3046
Promotional Banner

Topper's Solved these Questions

  • APPLICATIONS OF DERIVATIVES

    RS AGGARWAL|Exercise Exercise 11C|27 Videos

  • APPLICATIONS OF DERIVATIVES

    RS AGGARWAL|Exercise Exercise 11D|18 Videos

  • APPLICATIONS OF DERIVATIVES

    RS AGGARWAL|Exercise Exercise 11A|21 Videos

  • ADJOINT AND INVERSE OF A MATRIX

    RS AGGARWAL|Exercise Exercise 7|37 Videos

  • AREA OF BOUNDED REGIONS

    RS AGGARWAL|Exercise Exercise 17|39 Videos

Similar Questions

Explore conceptually related problems

Using differentials, find the approximate value of (log)_e 10.02 , it being given that (log)_e 10=2. 3026 .

Find the approximate value of log_(e)(101) given log_(e)10=2*3026

Find the approximate values of : log_(10)(1002)," given that "log_(10)e=0.4343 .

Find the value of log_(10)(10.1) given that log_(10) e=0.4343 .

Find the approximate value of (log)_(10)1005 , given that (log)_(10)e=0. 4343

Use differentials to find the approximate value of log_ _(e)(4.01), having given that log_(e)4=1.3863

Find the value of log_(10) (4.04) , it being given that log_(10) 4 = 0.6021 and log_(10) e = 0.4343

Using differentials, find the approximate value of (log)_(10)10. 1 , it being given that (log)_(10)e=0. 4343 .

Using differentials, find the approximate value of (log)_e 4.04 , it being given that (log)_(10)4=0. 6021 and (log)_(10)e=0. 4343 .