`intsqrt[1+sin2x]dx`

Options

A. `sinx + cosx + C`
B. `-sinx + cos x + C`
C. `sin x - cos x + C`
D. `-sin x - cos x + C`

Answer

C

Explanation

`(1+ sin 2x) = sin^(2) x + cos^(2)x + 2sin x cos x = (sinx +cosx)^(2)`
`sqrt(1+sin2x) = (sinx + cosx)`.