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int (sec^(2) x)/(" cosec "^(2)x) dx...

`int (sec^(2) x)/(" cosec "^(2)x) dx`

A

`tanx + x + C`

B

`tanx - x + C`

C

`-tanx + x + C`

D

`- tanx + x + C`

Text Solution

Verified by Experts

The correct Answer is:
B
`(sec^(2)x)/(cosec^(2)x) = (sin^(2)x)/(cos^(2)x) = tan^(2)x = (sec^(2) x - 1)`.
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