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int sin^(-1) (cosx) dx = ?...

`int sin^(-1) (cosx) dx = ?`

A

`cosec x + C`

B

`(pix)/(2) +(x^(2))/(2) + C`

C

`(pix)/(2) - (x^(2))/(2) + C`

D

`(x^(2))/(2) - (pix)/(2) + C`

Text Solution

Verified by Experts

The correct Answer is:
C
`sin^(-1) (cosx) = sin^(-1) {sin(pi/2 - x)} = (pi/2 - x)`.
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