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int(3x^2)/sqrt(9-16x^6)dx...

`int(3x^2)/sqrt(9-16x^6)dx`

A

`(1)/(4)sin^(-1)((x^(3))/(3))+C`

B

`(1)/(4)sin^(-1)((4x^(3))/(3))+C`

C

`4sin^(-1)((x^(3))/(4))+C`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

Put `x^(3)=t and 3x^(2)dx=dt. `
`therefore I=int(dt)/(sqrt(9-16t^(2)))=(1)/(4)int (dt)/(sqrt((9)/(16)-t^(2)))=(1)/(4).int(dt)/(sqrt(((3)/(4))^(2)-t^(2)))`
`=(1)/(4)sin^(-1) ""(t)/(((3)/(4)))+C=(1)/(4)sin^(-1)((4x^(3))/(3))+C.`
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