Solve the inequation `-3le3-2x lt9, x in R`. Represent the solution set on the real line.

Explanation

We have
`-3le3-2xlt9 rArr-3le3-2xand 3-2xlt9`.
Now, `-3le3-2xrArr-3+2xle3` [adding 2x on both sides]
`rArr2xle 6` [adding 3 on both sides]
`rArrx le 3` [dividing both sides by 2]
`rArrx in (-oo, 3]`.
And, `3-2xlt9 rArr -2x lt 6` [substracting 3 from both sides]
`rArr xgt -3` [dividing both sides by -2]
`rArr x in (-3,oo)`.
`therefore` solution set `=(-oo,3]nn(-3,oo)=(-3,3]`.
We may represent it on the number line as shown below.