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Find the equation of the line passing th...

Find the equation of the line passing through the point (0, 3) and perpendicular to the line x-2y+5=0.

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The correct Answer is:
`2x+y-3=0`
Given line is y=`(1)/(2)x+(5)/(2)."Its slope is "(1)/(2)`
`mxx(1)/(2)=-1 Rightarrow m=-2`
Let y=-2x+c be the straight line.
Sicne, it passes through (0,3), we have `3=(-2)xx0+c Rightarrow c=3`
`therefore m=-2 and c=3`.
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