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Find the equation of the line passing th...

Find the equation of the line passing through (-3, 5) and perpendicular to the line through the points (2, 5) and (-3,6).

Text Solution

Verified by Experts

The correct Answer is:
`5x-y+20=0`
Given points are A(2,5) and B(3,6)
Slope of AB=`(6-5)/(-3-2)=(-1)/(5)."So,"mxx((-1)/(5))=-1 Rightarrow mxx5`
`therefore "required equation i s"=(y-5)/(x+3)=5 Rightarrow 5x-y+20=0`
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