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A hot-air balloon is ascending at the ra...

A hot-air balloon is ascending at the rate of 12 m/s and is 80 m above the ground when a package is dropped over the side. (a) How long does the package take to reach the ground ? (b) With what speed does it hit the ground ?

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To solve the problem of the hot-air balloon and the dropped package, we can break it down into two parts: ### Part (a): Time taken for the package to reach the ground 1. **Understanding the motion**: The package is initially moving upward with the balloon at a speed of 12 m/s when dropped. It will first ascend until its velocity reaches 0 m/s, then it will descend to the ground. 2. **Calculate the time to reach the maximum height (t1)**: - Initial velocity (u) = 12 m/s (upward) ...
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A balloon is ascending at the rate of 9.8 m//s and is 39.2 m above the ground when a package is dropped. (a) How long does the package take to reach the ground? (b) with what speed does it hit the ground ? (g = 9.8 m//s^(2))

A hot-air balloon is ascending at a rate of 14 m/s at a height of 98 m above the ground when a packet is dropped from it. (a) With what speed does the packet reach the ground, and (b) how much time does the fall take ?

Knowledge Check

  • A ball is dropped from a 10 m height. How much time, it will take to reach the ground ?

    A
    1.41 s
    B
    0.58 s
    C
    2.34 s
    D
    none of these

  • A ball is dropped from a 10 m height ,How much time , it will take to reach the ground ?

    A
    `1.41` s
    B
    `0.58` s
    C
    `2.34` s
    D
    None of these

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    A balloon is ascending at the constant rate of 9.8 m//sec at a height of 98 m above the ground a packet is dropped from it. If time taken by the packet to reach the ground is (1 + sqrt(3lambda))sec . Find lambda . (Use g = 9.8 m//s^(2) )

    A ballon is assconding at the rate of 14 ms ^(-1) at a height of 98 m above the ground when velocity does it reach the ground ? Take g 9.8ms ^(-2) .

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