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The magnitudes of displacemwent veca and...

The magnitudes of displacemwent `veca and vecb` are 3 m anad 4m, respectively, and `vecc = veca + vecb.` Considering various orientations of `veca and vecb,` what are (a) the maximum possible magnitude for `vecc and (b)` the minimum possible magnitude ?

Text Solution

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To solve the problem, we need to find the maximum and minimum possible magnitudes of the resultant vector \( \vec{c} = \vec{a} + \vec{b} \), given the magnitudes of \( \vec{a} \) and \( \vec{b} \). ### Step-by-Step Solution: 1. **Identify the Magnitudes of Vectors**: - The magnitude of vector \( \vec{a} \) is given as \( |\vec{a}| = 3 \, \text{m} \). - The magnitude of vector \( \vec{b} \) is given as \( |\vec{b}| = 4 \, \text{m} \). ...
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Knowledge Check

  • The magnitudes of vectors vecA,vecB and vecC are 3,4 and 5 units respectively. If vecA+vecB= vecC , the angle between vecA and vecB is

    A
    `(pi)/2`
    B
    `cos^(-1)(0.6)`
    C
    `tan^(-1)(7/5)`
    D
    `(pi)/4`
  • The magnitudes of vectors vecA.vecB and vecC are respectively 12,5 and 13 unira and vecA+vecB=vecC , then the angle between vecA and vecB is :

    A
    0
    B
    `45^(@)`
    C
    `pi//2`
    D
    `pi//d`
  • If vecA = vecB + vecC and the magnitudes of vecA, vecB and vecC are 5,4 and 3 units respecetively, the angle between vecA and vecC is :

    A
    `cos ^(-1)(3//5)`
    B
    `cos ^(-1)(4//5)`
    C
    `pi//2`
    D
    `sin^(-1)(3//4)`
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