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If vectors vecA = hati + 2 hatj + 4 hatk...

If vectors `vecA = hati + 2 hatj + 4 hatk and vecB = 5 hati` represent the two sides of a triangle, then the third side of the triangle can have length equal to

A

6

B

`sqrt56`

C

both (a) and (b)

D

none of the above

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The correct Answer is:
To find the possible lengths of the third side of a triangle formed by the vectors \(\vec{A}\) and \(\vec{B}\), we can use the triangle inequality theorem. The theorem states that for any triangle with sides of lengths \(a\), \(b\), and \(c\), the following inequalities must hold: 1. \(a + b > c\) 2. \(a + c > b\) 3. \(b + c > a\) In this case, we will denote the lengths of the sides corresponding to the vectors \(\vec{A}\) and \(\vec{B}\) as follows: - Length of side corresponding to \(\vec{A}\): \( |\vec{A}| \) - Length of side corresponding to \(\vec{B}\): \( |\vec{B}| \) - Length of the third side: \( |\vec{C}| \) ### Step 1: Calculate the magnitudes of \(\vec{A}\) and \(\vec{B}\) Given: \[ \vec{A} = \hat{i} + 2\hat{j} + 4\hat{k} \] \[ \vec{B} = 5\hat{i} \] The magnitude of \(\vec{A}\) is calculated as: \[ |\vec{A}| = \sqrt{(1)^2 + (2)^2 + (4)^2} = \sqrt{1 + 4 + 16} = \sqrt{21} \] The magnitude of \(\vec{B}\) is calculated as: \[ |\vec{B}| = \sqrt{(5)^2} = \sqrt{25} = 5 \] ### Step 2: Apply the triangle inequality According to the triangle inequality, we have: 1. \( |\vec{A}| + |\vec{B}| > |\vec{C}| \) 2. \( |\vec{A}| + |\vec{C}| > |\vec{B}| \) 3. \( |\vec{B}| + |\vec{C}| > |\vec{A}| \) Substituting the magnitudes we calculated: 1. \( \sqrt{21} + 5 > |\vec{C}| \) 2. \( \sqrt{21} + |\vec{C}| > 5 \) 3. \( 5 + |\vec{C}| > \sqrt{21} \) ### Step 3: Solve the inequalities 1. From \( \sqrt{21} + 5 > |\vec{C}| \): \[ |\vec{C}| < \sqrt{21} + 5 \] 2. From \( \sqrt{21} + |\vec{C}| > 5 \): \[ |\vec{C}| > 5 - \sqrt{21} \] 3. From \( 5 + |\vec{C}| > \sqrt{21} \): \[ |\vec{C}| > \sqrt{21} - 5 \] ### Step 4: Combine the inequalities Now we need to find the range for \( |\vec{C}| \): - From \( |\vec{C}| < \sqrt{21} + 5 \) - From \( |\vec{C}| > 5 - \sqrt{21} \) - From \( |\vec{C}| > \sqrt{21} - 5 \) Calculating the numerical values: - \( \sqrt{21} \approx 4.58 \) - \( 5 - \sqrt{21} \approx 0.42 \) - \( \sqrt{21} - 5 \approx -0.42 \) (which is not a valid length) Thus, we can conclude that: \[ |\vec{C}| > 0.42 \] and \[ |\vec{C}| < 9.58 \quad (\text{since } \sqrt{21} + 5 \approx 9.58) \] ### Final Result The length of the third side can be in the range: \[ 0.42 < |\vec{C}| < 9.58 \]
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