(a) An astronaut whose height h is 1.70 m floats "feet down" in an orbiting space shuttle at distance `r = 6.77 xx 10^6`m away from the centerof Earth. What is the difference between the gravitational ecceleration at her feet and at her head ?

Explanation

To solve the problem of finding the difference in gravitational acceleration at the feet and head of an astronaut floating in a space shuttle, we will follow these steps:

### Step 1: Understand the Problem
The astronaut's height is given as \( h = 1.70 \, \text{m} \) and the distance from the center of the Earth to the astronaut's feet is \( r = 6.77 \times 10^6 \, \text{m} \). The height of the astronaut's head from the center of the Earth will be \( r' = r + h \).

### Step 2: Calculate the Distance to the Head
Calculate the distance from the center of the Earth to the astronaut's head:
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