What is the conductivity of a semiconductor sample having electron concentration of `5 xx 10^(18) m^(-3)` hole concentration of `5 xx 10^(19) m^(-3)`, electron mobility of `2.0 m^(2) V^(-1) s^(-1)` and hole mobility of `0.01 m^(2) V^(-1) s^(-1)?` (Take charge of electron as `1.6 xx 10^(-19)C)`
A semiconductor has an electron concentration of 0.45 xx 10^(12) m^(-3) and a hole concentration of 5.0 xx 10^(20) m^(-3) . Calculate its conductivity. Given electron mobility = 0.135 m^(2) V^(-1) s^(-1) , hole mobility = 0.048 m^(2) V^(-1) s^(-1) ,
A semiconductor is known to have an electron concentration of 5 xx 10^(13)//cm^(3) and hole concentration of 8 xx 10^(12)//cm^(3) . The semiconductor is
A semiconductor is known to have an electron concentric of 8xx10^(13)//cm^(3) and hole concentration of 5xx10^(12)//cm^(3) . The semiconductor is
A semiconductor has an electron concentration of 8xx10^(13) per cm^(3) and a hole concentration of 5xx10^(12) per cm^(3) . The electron mobilityis 25,000 cm^(2)V^(-1)sec^(-1) and the hole mobility is 100cm^(2)V^(-1)sec^(-1) and the hole mobility is 100cm^(2)V^(-1)sec^(-1) (i) The semiconductor is n -type (ii) the semiconductor is p -type (iii) the conductivity is 320m mho cm^(-1) (iv) the conductivity is 80m mho cm^(-1)
A semiconductor is known to have an electron concentration of 5xx10^(12) cm^(-3) and a hole concentration 8xx10^(13)cm^(-3) Is the semi-conductor n-type or p-type? What is the resistivity of the sample, if the electron mobility is 23,000 cm^(2) V^(-1)s^(-1) ? Take charge on electron, e=1.6xx10^(-19) C .
A type semiconductor sample has electron and hole concentration of 1.6 xx 10^(19) the electron and hole mobility in the sample is 1.2 m^(2) v^(-1) s^(-1) and 0.001 m^(2)v^(-1) s^(-1) respectively calculate the value of resistivity of the sample
What is the conductivity of a semiconductor (in Omega^(-1) m^(-1) ) if electron density = 5 xx 10^(12) cm^(-3) and hole density = 8 xx 10^(13) cm^(-3) ? (mu_(e) = 2.3 V^(-1) s^(-1)m^(2), mu_(h) = 0.01 m^(2) V^(-1) s^(-1))